Chem 116 - General Chemistry II

Chemistry Home
Solubility and Common Ion
Solubility of Silver Phosphate in Water
Video Solution
Solubility Product Constant
Video Solution
Molar Solubility of Silver Sulfate
A. pure water?
B. 0.50 M silver nitrate solution?
C. 0.30 M aluminum sulfate solution?
Video Solution
pH of Co(OH)3 Solution
Video Solution
pH and Molar Solubility of Mn(OH)2 Solution
Video Solution
pH and Molar Solubility of Fe(OH)3 in Water
Video Solution
Solubility of Salts in Acidic Solutions
Video Solution
Precipitation
Video Solution
Solubility of Zinc Carbonate in Various Solutions
Video Solution
Selective Precipitation
Salt
Ksp
ThF4
5.0x10-29
CaF2
3.2x10-11
LiF
1.7x10-3
What [F-] is needed to precipitate as much Th4+ and Ca2+ without precipitating the Li+?
At this [F-], what concentration of Th4+ and Ca2+ are left in solution and what percent of these ions have been precipitated?
Precipitation of Metal Bromides
Salt
Ksp
CuBr
5x10-9
PbBr2
6.6x10-6
AgBr
5.0x10-13
Video Solution
pH at Which a Precipitate Forms
Video Solution
Determining Molar Solubility
Video Solution
Identifying Precipitates
Video Solution
Molar Solubility
BaCrO4 Ksp = 1.2 X10-10
Mg(OH)2 Ksp = 5.6 X10-12
Au(OH)3 Ksp = 3.0 X10-6
Video Solution
Ksp
Video Solution
Calculating Molar Solubility
Calculate the molar solubility of Ca(OH)2 in pure water.
Calculate the molar solubility of Ca(OH)2 in 0.10 M Ca(NO3)2.
Calculate the molar solubility of Ca(OH)2 in 0.10 M NaCl.
Video Solution
Calculating pH of a Saturated Solution
KSP Mg(OH)2 = 5.6×10-12
Video Solution
Formation of a Precipitate
Video Solution
Solubility
lead(II) bromide
copper(II) hydroxide
iron(II) sulfide
Video Solution
Calculating Molar Solubility
Calculate the molar solubility of Mg(OH)2 in water buffered at a pH of 13.00.
Video Solution
Precipitation
KSP for Ag2CrO4 is 1.1×10–12 , KSP of BaCrO4 is 1.2×10–10.
Video Solution
Calculating KSP
Video Solution
Formation of a Precipitate
Ksp (BaCO3) = 2.6×10-9
3.0×10-3 M BaCl2 and 2.0×10-3 M Na2CO3
1.0×10-5 M Ba(NO3)2 and 4.0×10-5 M Na2CO3
Video Solution
Calculating Molar Solubility
Calculate the molar solubility of MgF2 in 0.10 M NaF
Calculate the molar solubility in 0.10 M MgCl2
Video Solution
Selective Precipitation I
At what concentration of Cl–(aq) will each salt just begin to precipitate (be at equilibrium)?
Ksp of PbCl2 = 1.7×10-5 Ksp of AgCl = 1.8×10-10 Ksp of Hg2Cl2 = 1.4×10-18
What concentration of chloride ion must be present to precipitate as much of the Hg22+ (as Hg2Cl2) as possible without precipitating the chlorides of Ag+, and Pb2+?
Video Solution
Selective Precipitation II
[Pb2+] = [Ag+] = [Hg22+ ] = 0.0015M.
We just determined that:
The PbCl2 system was at equilibrium when [Cl–] = 0.11 M,
The AgCl system was at equilibrium when [Cl–] = 1.2 X 10–7 M,
The Hg2Cl2 system was at equilibrium when [Cl–] = 3.1 X 10–8M.
Questions:
What concentration of Cl– ions is needed to precipitate all of the ions but Pb2+?
What is the concentration of Hg22+ ions in the solution at this concentration of Cl–?
Video Solution
Calculating Molar Solubility
Ag+(aq) forms the complex Ag(NH3)2+(aq) in a strong solution of ammonia. Calculate the molar solubility of AgCl in 3.0 M NH3
Ksp of AgCl = 1.8×10–10 Kf of Ag(NH3)2+(aq) = 1.7×107
Video Solution
Calculating Molar Solubility
Ksp of AgI = 8.3×10-17 and Kf of Ag(CN)2– = 7.1×1019
Video Solution
Calculating Molar Solubility
Ksp of AgI = 8.3×10-17 and Kf of Ag(S2O3)2-3 = 1.70×1013
Video Solution
Calculating Molar Solubility
Ksp of Cu(OH)2 = 1.6×10-19; Kf of [Cu(NH3)4]2+ = 1.1×1013
Video Solution