Oxalate Stoichiometry Part B - Back to Part A

Pyrolysis of FeC₂O₄x2H₂O will follow one of the following molecular equations. Balance each molecular equation.

a. FeC₂O₄x2H₂O (s) + O₂ (g) ➞ FeO (s) + H₂O (g) + CO₂ (g)

b.FeC₂O₄x2H₂O (s) + O₂ (g) ➞ Fe₂O₃ (s) + H₂O (g) + CO₂ (g)

c.FeC₂O₄x2H₂O (s) ➞ FeCO₃ (s) + H₂O (g) + CO (g)

For each of the possible pyrolysis reactions, calculate the theoretical yield (in grams) of the solid product, assuming that ou use 1.0 g FeC₂O₄x2H₂O and that the oxygen is the excess reactant. You will need to write in coefficients from the question above to balance the molecular equation.

b.FeC₂O₄x2H₂O (s) + O₂ (g) ➞ Fe₂O₃ (s) + H₂O (g) + CO₂ (g)

c.FeC₂O₄x2H₂O (s) ➞ FeCO₃ (s) + H₂O (g) + CO (g)